Calculation of the Focal Length

The derivation of this formula depends on the fact that an offset dish antenna represents a plane section through a paraboloid of revolution. Such a section has the following significant properties:
It follows from these properties that the offset angle of the dish, which is the angle between the plane of the section and the plane orthogonal to the axis of revolution, can be calculated from the width and height of the elliptical rim: cosine (offset angle) = width / height The properties of a parabola which make it possible to calculate the focal length of an offset dish when the point of origin of the curve isn't known are these:
This relationship between the slope of the chord and the gradient of the parabola is illustrated in the diagram below. The equation of the parabola is x = y^{2}/ 4a, where 'a' is the focal length. 
In the following diagram, the point P has been given the coordinates (x,y), and the end points of the chord BT, with length 2d and midpoint P, are derived from the semilength of the chord and the offset angle theta. 
Now calling the maximum depth of the dish curvature h, measured perpendicular to the chord, the depth parallel to the axis of the parabola will be h / cos(theta). The point of maximum depth, E, thus has the coordinates (x  h / cos(theta), y). 
To take a practical example, the appendix to http://www.qsl.net/n1bwt/chap5.pdf describes the calculation of the focal length of an offset dish by measuring three points along the curve of the dish, and using the coordinates to solve three quadratic equations with three unknowns  the focal length and the x and y coordinates of the point of origin  a very tedious calculation. The text refers to a dish with a height of 500 mm, a width of 460 mm, and a maximum depth of 43 mm at a point 228 mm up the chord from the bottom edge. This gives the coordinates of (0, 0), (49.8, 226.6) and (196, 460), which are used to write and simultaneously solve three equations of the form 4a.(X + Xo) = (Y + Yo)^{2} where Xo and Yo refer to the unknown position of the origin. Solving these
equations gives a focal length of 282.89 mm. focal length = 460^{3} / (16 x 43 x 500) = 282.95 mm The result is thus in almost perfect agreement with that obtained by the
solution of three simultaneous equations  the slight difference being due to
the fact that the measurement given for the position of the point of maximum
depth isn't strictly accurate. But as we have shown, it is isn't necessary to
know this dimension. 
The Position of the LNB Yo = 2.a.tan (theta)  w / 2 and from the equation of the parabola: Xo = Yo^{2} / 4.a The following calculation makes use of the fact that every point on a parabola is the same distance from the focal point as it is from a line known as the directrix, which in the present case is a line drawn parallel to the y axis through the point (a, 0), where 'a' is the focal length of the parabola. 
It follows that the distance BF from the lower rim of the dish to the focal point at the LNB is obtained simply by adding the focal length 'a' to the xcoordinate: BF = BD = Xo + a The point A on the upper rim of the dish is connected to the point B by the chord AB at an angle to the y axis equal to the offset angle theta. Thus the distance AF to the focal point will be: AF = AC = Xo + a + AB.sin (theta) where AB is the height of the dish D or 2.d in our previous working. In practice Xo is often close to zero and may be neglected. Now applying these equations to our worked example, we find that Xo is 0.1 mm, and hence BF is 283 mm and AF is 479 mm. The abovecited text suggests a "top string length" of 466476 mm, and reaches the conclusion that the origin of the parabola is located on the lower rim of the dish. Since Yo is only one centimetre, this was arguably the designer's intention. 
Comments to John Legon